Complete the chart below to show the properties that hold true for the quadrilateral given in each row.

Mathematics

1 answer:

puteri [66]2 years ago

6 0

Hey there!

Opposite sides are congruent:

all of them

opposite angles are congruent

rectangle and square

all sides are congruent

rhombus and square

diagonals congruent:

rectangle, rhombus, and square

diagonals are perpendicular

square and rhombus

Have a terrificly amazing day!

You might be interested in

the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the

Taya2010 [7]

The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5

Y=14-x
=14-5
=9

So the two digit number is
10y+x
=90+5
=95

5 0

3 years ago

The first three steps in determining the solution set of the system of equations algebraically are shown in the table. y = −x2 +

lianna [129]

You have a system of equations $\left \{ {{y = -x^2+2x-9} \atop {y =-6x+6}} \right.$ .

1. Substitude right side of second equation into the left side of the first equation: $-6x+6=-x^2+2x-9$ .

2. Solve this equation:
$x^2-2x+9-6x+6=0, \\ x^2-8x+15=0, \\ D=(-8)^2-4\cdot 1\cdot 15=64-60=4, \\ \sqrt{D}=2, \\ x_{1,2}=\dfrac{8\pm 2}{2 } =3,5$ .

3. Find y:
for $x_1=3, y_1=-6\cdot 3+6=-18+6=-12$ ,
for $x_2=5, y_2=-6\cdot 5+6=-30+6=-24$ .

4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.

7 0

3 years ago

Read 2 more answers

Kyle wants to wrap the box in wrapping paper. A rectangular prism with a length of 18 inches, width of 6 inches, and height of 3

m_a_m_a [10]

Answer:

180 squared inches

Step-by-step explanation:

SA= L*W, L*H, H*W

108+54+18

=180

3 0