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solniwko [45]
3 years ago
12

H(x)= 9/x( x^2-49) Determine the domain of the function

Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer: The domain of the function h(x) = \frac{9}{x(x^2-49)} is:

Interval Notation: (-∞ , -7) ∪ (-7 , 0) ∪ (0 , 7) ∪ (7, ∞)

Set-Builder Notation: { x | x ≠ 0 , 7 , -7 }

All real numbers besides 0, 7, and -7.

Step-by-step explanation:

In order to find the domain of your rational function, we need to simplify it:

h(x) = \frac{9}{x(x^2-49)} = \frac{9}{(x)(x+7)(x-7)}

Remember, most of the time, the domain of a rational function consists of all real numbers besides zero.

To find the domain, we equal the equations in the denominator to zero.

x=0

x+7=0 --> x=-7

x-7=0 --> x=7

So all real numbers except for 0, -7, and 7 are in the domain of this rational function.

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Of all the species in the world, 4 out of every 5 are insects what percentage of species are insects
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Answer:

80%

Step-by-step explanation:

So you basically, just make it a ratio. Since a percentage is out of 100, just make the 5 into 100. To get 5 to 100, you times 20. Then you do the same thing to the 4 which you get 80.

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3 years ago
Calculate the perimeter of this shape.
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Step-by-step explanation:

Hello there!

Again, just double the given sides.

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what is the maximum, minimum, quartile 1, median, quartile 3, range, interquartlie range of these numbers " 46,48,50,52, and 54"
Gekata [30.6K]
Min=46
Max=54
1 quartile= 48
Median=50
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46/48 percent is 95.83%
4 0
2 years ago
Read 2 more answers
What is the equation of the line that passes through the points (-3,5) (6,8)
Ratling [72]

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
Can you please find the domain and the range
ohaa [14]

Answer:

  • domain: (-4, ∞)
  • range: [-4, ∞)

Step-by-step explanation:

The domain is the horizontal extent of the function. This function is defined for all values of x greater than (but not including) -4. Its domain is (-4, ∞).

__

The range is the vertical extent of the function. This function gives output values of any number greater than or equal to -4. Its range is [-4, ∞).

__

Interval notation uses square brackets when the value is included in the interval. It uses round brackets (parentheses) when the end value is not included in the interval. ∞ is not a number, so that end always gets a round bracket.

6 0
3 years ago
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