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lesantik [10]
2 years ago
15

Which values in this data set are outliers? 48, 52, 56, 64, 61, 20, 48, 51, 58, 48, 78 Select Outlier or Not Outlier for each va

lue. Value Outlier Not Outlier 20 Outlier – 20 Not Outlier – 20 48 Outlier – 48 Not Outlier – 48 64 Outlier – 64 Not Outlier – 64 78 Outlier – 78 Not Outlier – 78.
Mathematics
1 answer:
Marizza181 [45]2 years ago
6 0

Outlier is a data point that is different from the rest of the data. The outliers in the dataset will be 20 and 78.

<h3>What is a Scatter plot?</h3>

A scatter plot is also known as a scatter chart, a scatter graph that uses dots to represent values for two different numeric variables. Each dot on the graph represents particular data on both axes.

<h3>What is an Outlier?</h3>

An outlier is a data point that is different from the rest of the data.

If we keenly observe the data set that is given to us, 48, 52, 56, 64, 61, 20, 48, 51, 58, 48, 78; the range of the data set that is given to us lies mostly between the 48 to 68, therefore, the data point that is the outlier for this data set are 20 and 78.

Hence, the outliers in the dataset will be 20 and 78.

Learn more about Outlier:

brainly.com/question/9933184

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3 years ago
The cabinet that will enclose the Acrosonic model D loudspeaker system will be rectangular and will have an internal volume of 2
Kazeer [188]

Answer:

Dimensions of cabinet

x (wide) = 1.93 ft

y (hight) = 2.895 ft

p (depth) =0.43 ft

Step-by-step explanation:

Dimensions of cabinet

y  height

x  wide

p  deph

From problem statement

y = 1.5 x       V = y * x * p      V = 1.5*x²p      but p = V/y*x     p = 2.4/1.5 x²

p = 1.6 / x²

Then

Area of top and bottom    A₁ = 2*x*p  ⇒   2*x*1.6/x²  

A₁  = 3.2 /x

And cost  in $ C₁  = 0,9 * 3.2 /x     ⇒   C₁  = 2.88/x

Area of sides (front and rear not included)

A₂ = 2*y *p      A₂ = 3*x*1.6/x²    A₂ = 4.8/x

And cost in $ C₂ = 0.9 * 4.8 /x    C₂ = 4.32 /x

Area of  front and rear   A₃  =2* y*x    A₃  = 2*1.5 *x²    A₃ = 3x²

And cost  C₃ = 0.3 * 3/x²    =  0.9/x²

Total cost  C(x) = C₁  + C₂ + C₃            C(x) = 2.88/x  +  4.32/x + 0.9x²

Taking derivatives

C´(x)  =  -2.88/x² - 4.32 /x² + 0.9 x

C´(x) = 0             -2.88/x² - 4.32/x² + 0.9 x = 0     -2.88 - 4.32 + 0.9 x³ = 0

-7.2 + x³ = 0    x³ = 7.2    

x = 1.93 ft        y = 1.5*1.93  = 2.895 ft    and p = 0.43 ft

               

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