This can help you
a) since it is discrete we need to think about the sum thing
it it was continuous we would look at an integral thing
so I think if I remember correctly we need to find c such that
<span><span>∑<span>i=0</span>3</span>c(<span>x2</span>+4)=1
b) </span>
problem b is a similar setup
Answer:
Option B
Step-by-step explanation:
Given quadratic equation is,
12a² + 9a + 7 = 0
By comparing this equation with standard quadratic equation,
hx² + kx + c = 0
h = 12, k = 9 and c = 7
By using quadratic formula,
a = 
= 
= 
= 
= 
a = 
Therefore, Option B will be the correct option.
Answer:
x = 20
y = 100
Step-by-step explanation:
To figure out x do this.
3x + 2x = 7x - 40 (collect like terms)
5x = 7x -40 (subtract 7x on both sides)
-2x = -40 (divide by -2 on both sides)
x = 20
Plug in to get y
Since 7x - 40 and y are vertical they equal the same amount
7(20) - 40 = y (multiply 7 by 20)
140 - 40 = y (collect like terms)
100 = y
Hope this helps ya! Keep smiling!
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
<h3>What is the range of a quadratic equation?</h3>
In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.
x = - 9
y = (2 / 3) · (- 9)² - 6
y = 48
x = - 6
y = (2 / 3) · (- 6)² - 6
y = 18
x = - 3
y = (2 / 3) · (- 3)² - 6
y = 0
x = 0
y = (2 / 3) · 0² - 6
y = - 6
x = 3
y = (2 / 3) · 3² - 6
y = 0
x = 6
y = (2 / 3) · 6² - 6
y = 18
x = 9
y = (2 / 3) · 9² - 6
y = 48
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
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Answer:
okay i will answer but i dont see the question
Step-by-step explanation:
