![f(x)=(1-x^2)^{\frac{2}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3}(1-x^2)^{-\frac{1}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3\sqrt[3]{1-x^2}}](https://tex.z-dn.net/?f=f%28x%29%3D%281-x%5E2%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%7D%281-x%5E2%29%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B1-x%5E2%7D%7D)
when it comes to a rational expression, we can get critical points from, zeroing the derivative "and" from zeroing the denominator alone, however the denominator provides critical valid points that are either "asymptotic" or "cuspics", namely that the function is not differentiable or not a "smooth line" at such spot.
if we get the critical points from the denominator on this one, we get x = ±1, both of which are cuspics. Check the picture below.
The answer is 6ft hope its helps.Have a good day!
Rewriting the question, the given lengths that were cut from the board were 30 3/4 inches, 12 1/4 inches, and 16 1/4 inches. To obtain the remaining length of the board, all of the measurements cut are to be added and subtracted from 72 inches. This is shown below:
30 3/4 + 12 1/4 + 16 1/4 = 237/4 = 59.25 inches.
Remaining length of board = 72 - 59.25 = 12.75 inches.
Therefore, there will be 12.75 inches remaining of the board.
$312.50 = p x 0.25 x 25
divided by 25
12.50 = p x 0.25
divide by 0.25
50 = principal
Just ask if anything is unclear
Answer:
I got 126.12 in my notes
Step-by-step explanation:
