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Margarita [4]
2 years ago
6

Tutorial from edmentum please help!

Mathematics
1 answer:
evablogger [386]2 years ago
6 0

Answer:

(\frac{3}{8} )^{-2} (\frac{1}{3}* \frac{3}{8})^3 ( \frac{1}{3} )^4

(\frac{3^-2}{8^-2} ) (\frac{1^3}{3^3}* \frac{3^3}{8^3}) ( \frac{1^4}{3^4} )

(\frac{64}{9} ) (\frac{1}{27}* \frac{27}{512}) ( \frac{1}{81} )

(\frac{64}{9} ) (\frac{1}{512}) ( \frac{1}{81} )

Simplifies to= \frac{1}{5832}

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