Pls help I’ll brainlest

zimovet [89]

Answer: #1 is the answer. Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.

Step-by-step explanation: Parallel Lines: Definition: We say that two lines (on the same plane) are parallel to each other if they never intersect each other, ragardless of how far they are extended on either side. Pictorially, parallel lines run along each other like the tracks of a train.

7 0

3 years ago

Given mn, find the value of x.<br> 108

adoni [48]

Answer:

72 degrees

Step-by-step explanation:

Referencing off of line t being a straight line, a straight line is 180 degrees. If you subtract 108 from 180, you would get 72. Since this intersecting line is going through 2 paralel lines, the 2 groupings of angles reflect each other.

3 0

3 years ago

What will happen to me if I get a 0 on my homework and it's worth 20% of my grade? This is the 3rd time this happened.

IrinaVladis [17]

Your overall grade will go down. I'd try to ask your teacher if you can make them up.

7 0

3 years ago

Unknown angle problems (with algebra)

lubasha [3.4K]

Answer: x = 20 degree
3x = 3×20 which is 60 degree
And the other one is 100 degree
Add all the number 100+60+20 degree is 180 degree

7 0

3 years ago

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

3 years ago