Suppose that scores on an exam are normally distributed with mean 80 and standard deviation 5, and that scores are not rounded.
1 answer:
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solve for the indicated variable means isolate that variable.
Ans(7)
P=IRT (T)
that means solve for T or make T alone on one side of equal.
To do that we just need to move IR on the left side
So we get:
Hence final answer will be
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Ans(8)
2x-3y=8 (y)
-3y=8-2x
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Ans(9)
V=LWH (L)
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Ans(10)
A=2(L+W) (w)
A=2L+2W
A-2L=2W
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Ans(11)
ax+by=c (y)
by=c-ax
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Ans(12)
(R)
PN=R-C
PN+C=R
R=PN+C
Answer:
y=-3x-14
Step-by-step explanation:
