20 ÷ 2 (5,5)
20 ÷ 2 (25)
20 ÷ 50
.4
-12/16 <span>< </span>3/4 <span>= </span>9/12 <span>< </span>2 <span>< </span>3 5/8
Solution :
Given initial population = 300
Final population after 1 day = 800
Number of days = 6
∴ 
P(0) = 300 P(1) = 300
We need to find P(8).
When P(0) = 300
∴ c = 300
∴ 
When P(1) = 800
∴ k = 750
So, P(8) is
= 11,614
So the population becomes 11,614 after 8 days.
Answer:
D. 40
Step-by-step explanation:
Interquartile range is the difference between the upper quartile value (Q3) and the lower quartile value (Q1).
In a box plot, Q1 is located at the beginning of the edge of the rectangular box from our left, while the Q3 is located at the end of the edge of the rectangular box to our right.
Interquartile range for City A = 70 - 40 = 30
Interquartile range for City B = 80 - 40
Therefore, city B has greater variability. The interquartile range is 40.
Answer:
x = 1 and y = 7
Step-by-step explanation:
First, you substitute the y into the first equation
-5x+2(7x)=9
-5x+14x=9
9x=9
x=1
Then put the x into the equation to find y
This is if you substitute using the second equation
y=7(1)
y=7
