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Strike441 [17]
3 years ago
11

Answer ASAP THANKKK YOUUUUU

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

D. 40

Step-by-step explanation:

Interquartile range is the difference between the upper quartile value (Q3) and the lower quartile value (Q1).

In a box plot, Q1 is located at the beginning of the edge of the rectangular box from our left, while the Q3 is located at the end of the edge of the rectangular box to our right.

Interquartile range for City A = 70 - 40 = 30

Interquartile range for City B = 80 - 40

Therefore, city B has greater variability. The interquartile range is 40.

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The total cost to rent 5 chairs and 3 tables is $27. The total cost to rent 2 chairs and 12 tables is $81. What is the cost to r
kati45 [8]

The cost to rent each chair is $1.5 and cost to rent each table is $6.5

<h3>Applications of systems of linear equations </h3>

From the question, we are to determine the cost to rent each chair and each table

Let c represent chair

and

t represent table

From the given information,

The total cost to rent 5 chairs and 3 tables is $27

That is,

5c + 3t = 27 ------------ (1)

Also,

The total cost to rent 2 chairs and 12 tables is $81

That is,

2c + 12t = 81 ---------- (2)

Now, solve the equations simultaneously

5c + 3t = 27 ------------ (1)

2c + 12t = 81 ---------- (2)

Multiply equation (1) by 2 and multiply equation (2) by 5

2 × [5c + 3t = 27 ]

5 × [2c + 12t = 81 ]

10c + 6t = 54        ------------- (3)

10c + 60t = 405   ------------- (4)

Subtract equation (4) from equation (3)

10c + 6t = 54        

10c + 60t = 405

---------------------------

-54t = -351

t = -351/-54

t = 6.5

Substitute the value of t into equation (2)
2c + 12t = 81

2c + 12(6.5) = 81

2c + 78 = 81

2c = 81 - 78

2c = 3

c = 3/2

c = 1.5

∴ The cost of chair is $1.5 and cost of table is $6.5

Hence, the cost to rent each chair is $1.5 and cost to rent each table is $6.5

Learn more on Solving system of linear equations here: brainly.com/question/13729904

#SPJ1

8 0
2 years ago
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