Answer:
A) 21.02°
B) 26.74°
C) 22.79°
D) DNE
Step-by-step explanation:
We can solve the equation for the angle:
D = 672·sin(2θ)
D/672 = sin(2θ)
arcsin(D/672) = 2θ
θ = arcsin(D/672)/2
A) For D = 450, θ = arcsin(450/672)/2 = 21.0198° ≈ 21.02°
B) For D = 540, θ = arcsin(540/672)/2 = 26.7363° ≈ 26.74°
C) For D = 480, θ = arcsin(480/672)/2 = 22.7923° ≈ 22.79°
D) For D = 720, θ = arcsin(720/672)/2 = DNE
Let the kite is the quadrilateral A B C D with the two pairs of adjacent congruent sides. (Please find the attached diagram also)
Now, its given in question, see from figure,
AB is congruent to AD
BC is congruent to DC
So, let us join the points A & C to form AC ; and points B and D to form BD.
So, AC is common side to triangles ABC and ADC.
So, Because AB ≈AD
BC ≈ DC
And, AC is common, therefore,
triangle ABC is congruent to triangle ADC
⇒∠ ABC ≈ ∠ADC
The above are the angle.
