All categories

2 years ago

What aspect of the town are most at risk for damage by the fire??

Mathematics

1 answer:

Stolb23 [73]2 years ago

7 0

Answer:

Trees.

Step-by-step explanation:

The houses look sturdy, and not that flammable. The trees and grass are very plentiful, so they would spread easily.

Please clarify if this wasn't what you were asking.

You might be interested in

Seqouya has 1/2 of a liter of apple juice which fills 1/3 of her glass. How many glasses will 1 liter of apple juice fill

zavuch27 [327]

Answer:

2/3 of her glasses

Step-by-step explanation:

If 1/2 liter apple juice fills 1/3 of her glasses, then twice that volume will fill twice as many glasses: 2/3 of her glasses.

4 0

3 years ago

Determine whether the statement is always, sometimes, or never true. Complete the explanation. In parallelogram MNPQ, the diagon

Crank

This is never true. In a parallelogram, the diagonals will always bisect each other. Thus, each of these segments would always have to be equal.

4 0

3 years ago

Ali Makes a Four digit number . The sum of the digit is 4 . The thousands digit and the unit digit are the same. The hundreds di

Tcecarenko [31]

Answer:

1021

Step-by-step explanation:

1+1=2 and it needs to add up to 4 so you add in another 2 in the only place left for it to go which is in the tens place because the first and last number have to be the same and 0 has to go in the hundreds place.

3 0

1 year ago

2. You (or your parents) are purchasing a used car. Which interest rate do you use?

Svetlanka [38]

Answer:

New secured 4.50% is the best option.

4 0

2 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

$A=P(1+r)^x$

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

$1000=P(1+r)^0\implies P = 1000$

A = 1900 when x = 1,

$1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9$

Thus, the required function that represents the population after x days,

$A=1900(1+0.9)^x=1900(1.9)^x$

If x = 4,

The number of mosquito after 4 days,

$A=1900(1.9)^4 = 24760.99\approx 24761$

If A = 60,000,

$60000 = 1900(1.9)^x$

$\frac{600}{19}=1.9^x$

Taking log both sides,

$\log(\frac{600}{19})=x\log 1.9$

$\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4$

Thus, there will 60,000 mosquitoes after 5 days.

6 0

3 years ago