Any second part or anything else to look at?
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
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To adapt this rule to this particular question replace h with 0, as the
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upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
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Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
Answer:
y = - 3x + 7
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (2, 1) and (x₂, y₂ ) = (5, - 8)
m = 
= 
= - 3 , thus
y = - 3x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (2, 1) , then
1 = - 6 + c ⇒ c = 1 + 6 = 7
y = - 3x + 7 ← equation of line
The top left is alternate exterior. The top right is none of them. The middle left is corresponding. The middle right is alternate interior. And the bottom one is corresponding.
Answer:
8 < 6x
Step-by-step explanation:
Just write what you see by the letters
