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Sveta_85 [38]
3 years ago
6

Because they are alternate interior angles.

Mathematics
1 answer:
ycow [4]3 years ago
3 0
Because they are corresponding. That means that they sit in the exact same place within their own group of angles. That means, however, that lines a and b have to parallel. It's not marked that they are, but I'm assuming they must be by the answer choices you provided.
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A man is paid a basic hourly rate of $7.00 and is paid
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Step-by-step explanation:

This would be 50x7=350

And 60 is 10 over 50, we half his salary($3.50), and multiply $3.50 by that extra 10. coming to $35. Add 35 to 350 to get his $385 60 day salary

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N ∆ABC, if sin A = and tan A = , then what is cos A?
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A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle o
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Answer:

a. 25.98i - 15j mi/h

b. 1.71i + 4.7j mi/h

c. 27.69i -10.3j mi/h

Step-by-step explanation:

a. Identify the ship's vector

Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h

Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h

b. Identify the water current's vector

Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h

Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h

c. Identify the vector representing the ship's actual motion.

The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.

V = v + v'

= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h

= (25.98i + 1.71i + 4.7j - 15j )mi/h

= 27.68i -10.3j mi/h

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