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2 years ago

I do not know this answer

Mathematics

1 answer:

ch4aika [34]2 years ago

7 0

Answer:

K=(3,6)

Step-by-step explanation:

If you reflect it over the y-axis the first number will change to a positive and the second number will stay the same.

Hope this helps have a great day! :)

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What is 2/5 divided by -1/2 minus 3/2

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Answer:

$- \frac{23}{10}$

Step-by-step explanation:

$\frac{2}{5} \div \frac{ - 1}{2} - \frac{3}{2}$

➡️ $- \frac{2}{5} \times 2 - \frac{3}{2}$

➡️ $- \frac{4}{5} - \frac{3}{2}$

➡️ $- \frac{23}{10}$

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An electrical power plant burns 285 barrels of oil each day to

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Step-by-step explanation:

1 day use 285 barrels of oil

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3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

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3 years ago

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Vaselesa [24]

Answer:

Step-by-step explanation:

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2 years ago

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svetoff [14.1K]

Answer:

I think it's

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