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Eddi Din [679]
2 years ago
10

I do not know this answer

Mathematics
1 answer:
ch4aika [34]2 years ago
7 0

Answer:

K=(3,6)

Step-by-step explanation:

If you reflect it over the y-axis the first number will change to a positive and the second number will stay the same.

Hope this helps have a great day! :)

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1) What is the solution to x - 5 = 27?
Phoenix [80]
X - 5 = 27

Isolate the x, add 5 to both sides (because of equal sign)

x - 5 = 27
x - 5 (+5) = 27 (+5)
x = 27 + 5
x = 32

x = 32 is your answer

hope this helps
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How can I construct a truth table for ~(p ^ q)?
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Attached below is a step by step process of arriving at the answer. 

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3 years ago
7(9) = 9(7)
vivado [14]

Answer:

A) Commutative

Step-by-step explanation:

The Associative has to do with re-grouping numbers. There are only two numbers so this does not apply here. Commutative is where you change the order; that's what the equation is demonstrating.

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3 years ago
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A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i
goldfiish [28.3K]

Answer:

  • P(t) = 100·2.3^t
  • 529 after 2 hours
  • 441 per hour, rate of growth at 2 hours
  • 5.5 hours to reach 10,000

Step-by-step explanation:

It often works well to write an exponential expression as ...

   value = (initial value)×(growth factor)^(t/(growth period))

(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...

  P(t) = 100·2.3^t

__

(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours

__

(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t

  P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour

__

(d) We want to find t such that ...

  P(t) = 10000

  100·2.3^t = 10000 . . . substitute for P(t)

  2.3^t = 100 . . . . . . . . divide by 100

  t·log(2.3) = log(100)

  t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000

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3 years ago
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