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3 years ago

Find the midpoint of (1,-7),(1, 11)

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

4 0

The answer to your question is(1,2)

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Mai and Tyler work on the equation 2/5b+1=-11 together. Mais soulution is b=-25 and Tyler’s is b=-28. Here is their work. Do you

Anika [276]

Answer:

No I don't agree with their solution; both their answers are wrong.

Correct answer is $b=-30$ .

Step-by-step explanation:

Given:

$\frac{2}{5}b+1=-11$

Now given:

According to Mai $b = -25$ and According to Tyler $b = -28$

Now we need to find which of them is correct.

So we will solve the given equation we get;

$\frac{2}{5}b+1=-11$

Subtracting both side by 1 we get;

$\frac{2}{5}b+1-1=-11-1\\\\\frac{2}{5}b =-12$

Now Multiplying both side $\frac{5}{2}$ we get;

$\frac{2}{5}b\times\frac{5}{2}= -12 \times \frac{5}{2}\\\\b=-6\times 5\\\\b=-30$

Hence both of them are incorrect, correct answer is $b=-30$ .

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3 years ago

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Svetach [21]

Answer:

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3 years ago

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How many liters give u 3.1KL

MariettaO [177]

Answer:

3100 liters

Step-by-step explanation:

multiply the value by 1000

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3 years ago

A line has a slope of -2 and a y-intercept of –3. Graph the line using the slope and y-intercept.

masha68 [24]

Answer:The answer is 231

Step-by-step explanation:

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4 years ago

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Find the volume of a pyramid with a square base, where the perimeter of the base is 8.2\text{ cm}8.2 cm and the height of the py

7nadin3 [17]

Answer:

$V=18.2cm^3$

Step-by-step explanation:

The volume of the pyramid is given by:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height.

We know that the height is:

$h=13cm$

Thus we need to find the area of the square at the base.

The perimeter of the square is:

$p=8.2cm$

this means that the length of the sides of the square is :

$l=\frac{p}{4}\\ \\l=\frac{8.2cm}{4}\\ \\l=2.05cm$

Now we can find the area of the base which the area of the square:

$A_{b}=l^2\\A_b=(2.05cm)^2\\A_b=4.2025cm^2$

and finally we find the volume:

$V=\frac{A_{b}h}{3}$

$V=\frac{(4.2025cm^2)(13cm)}{3}\\ \\V=\frac{54.6325cm^3}{3}\\ \\V=18.2108cm^3$

Which rounded to the nearest tenth of a cubic centimeter is: $V=18.2cm^3$

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3 years ago