I think it may be true, please correct me if i am wrong
(a) without replacement:
P(S)=13/52=1/4
P(SS)=(1/4)*(12/51)=1/17
Probability of selecting two spades without replacement is 1/17.
(b) with replacement
P(S)=13/52=1/4
P(SS)=(1/4)(13/52)=1/16
Probability of selecting two spades with replacement is 1/16.
Answer: The area is 201.06
Answer:
B. 20x^4-39x^3+26x^2-6x
Step-by-step explanation:
(5x^2-6x+2)*(4x^2-3x)
20x^4 -15x^3 -24x^3 + 18 x^2 +8x^2 - 6x
20x^4 -39x^3 + 26x^2 - 6x
