The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Answer:
1.1032
2.6
3.16
4.35:50 I think
Step-by-step explanation:
Please send more context as of the "green numbers".
For the multiplication,
i 49 x 10 = 490
490 ÷ 10 = 49
ii 2.3 <span>÷ 10 = 0.23
0.23 x 10 = 2.3
iii 0.034 x 1000 = 34
34 </span><span>÷ 1000 = 0.034
iv 876 </span><span>÷ 100 = 8.76
8.76 x 100 = 876
Hope this helps :)</span>
The answer to this question is 96cm2
Answer:
it a or the first one or whatevr u wanna call it jsut #1
Step-by-step explanation:
