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3 years ago

What is the circumference of a circle with radius 3.5cm. Take [Pi=22/7]

Mathematics

2 answers:

Nitella [24]3 years ago

5 0

Answer:

22cm

Step-by-step explanation:

Circumference of a circle = 2πr

π = 22/7

r = 3.5

Circumference of a circle = 2 × (22/7) × 3.5

Circumference of a circle = 22cm.

GarryVolchara [31]3 years ago

5 0

Answer:

22cm

Step-by-step explanation:

circumference of a circle=2πr
2×22/7×3.5
2×22×0.5
44×0.5
22

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3 years ago

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3 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

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$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

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2 years ago

What is the circumference of a circle with radius 3.5cm. Take [Pi=22/7]​

What is the circumference of a circle with radius 3.5cm. Take [Pi=22/7]