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3 years ago

Is the answer to this problem right

Mathematics

2 answers:

strojnjashka [21]3 years ago

8 0

Answer: No, that's incorrect.

Step-by-step explanation: Opt. 2 is = 59*2 = 118 and Opt. 5 is = 59*3 = 177

So the answer is Opt. 4 and 6

Morgarella [4.7K]3 years ago

6 0

Answer:

it should be option 2 and 4

Step-by-step explanation:

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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago

Bill and matt are discussing their children. bill tells matt that he has 3 kids, and the product of their ages is 72. he also te

zloy xaker [14]

Bill tells Matt that he has 3 kids. This means that in this item, we have three unknowns, those are the ages of the three kids. First, the product of the ages is 72.
(x)(y)(z) = 72
Also, for the sum of their ages, we have
x + y + z =?

There are three variables in the equation which means that 3 equations should also be presented to determine the ages of the three children.

4 0

3 years ago

Simplify 7x^2+10x^2+5y^3

vova2212 [387]

7x^2+10x^2= 17x^2
Answer. 17x^2+5y^3

6 0

2 years ago

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The expression (q16)(q−5)2 is equivalent to qn. What is the value of n? 42 22 -160 13

Lelu [443]

Answer:

Step-by-step explanation: