The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
Yeah sure, but i need to see the picture to get your answer
Well you see here, you need to take attest pre-calculus to answer this question. I am in 6th grade.
Answer:
D. (7,5)
Step-by-step explanation:
Imagine a full parallelogram, complete the shape from there
Answer:
Which of the following is a common sign that a chemical change has occurred?
Step-by-step explanation:
rodrickkkkkkkkkkkkkk
