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erik [133]
3 years ago
10

A school sing games played 160 games and won 65 percent of them how many games did the team win?

Mathematics
1 answer:
jonny [76]3 years ago
8 0
The team won 104 games
160 * 0.65 = 104
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At most, Charlie can spend $50 on bread and turkey for a picnic. He already bought a loaf of bread for $2 and will buy turkey th
Andre45 [30]
50 > or = to 2 + 6x X < or = to 8 He can buy 8 pounds of turkey
3 0
3 years ago
Find the area of the regular polygon
olasank [31]

area = 44.0467 \: cm {}^{2}

<h3>step by step explanation </h3>

● area of regular polygon Formulas ,

⟹a = \frac{l^{2}n}{4tan(\frac{\pi }{n)}}

● now finding the area of regular polygon,

⟹\frac{4 {}^{2} \times 8 }{ 4 \: tan \:  \binom{180}{5} }

⟹a =  \frac{128}{4 \times 0.7265}

⟹a = 44.0467 \: cm {}^{2}

Hope it's helps you

4 0
3 years ago
Which are undefined terms that can be used to define other terms?
zubka84 [21]

Answer:

Point, Line, Plane

Step-by-step explanation: They are undefined terms because its is easier to define them using examples rather than word for word

5 0
3 years ago
Which of these functions has a domain of all real numbers except x=4.1?
nika2105 [10]

Answer:

(A)y=\frac{2.5}{x-4.1} + 2.8

Step-by-step explanation:

In the expressions, the value at which the domain of the function will be the set of all real numbers except x=4.1 is the value at which 4.1 makes the denominator equal to zero, i.e makes the fraction undefined.

Given the options

(A)y=\frac{2.5}{x-4.1} + 2.8

Setting the denominator to zero, x-4.1=0, x=4.1. The fraction is undefined at x=4.1

(B)y=\frac{2.8}{x+4.1} -2.5

Setting the denominator to zero, x+4.1=0, x=-4.1. The fraction is undefined at x=-4.1

(C)y=\frac{4.1}{x-2.8} +2.5

Setting the denominator to zero, x-2.8=0, x=2.8. The fraction is undefined at x=2.8

(D)y=\frac{4.1}{x-2.5} +2.8

Setting the denominator to zero, x-2.5=0, x=2.5. The fraction is undefined at x=2.5

Therefore, function that has a domain of all real numbers except x=4.1 is:

(A)y=\frac{2.5}{x-4.1} + 2.8

4 0
3 years ago
A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center o
natta225 [31]

Answer: 3.751*10^18kg

Step-by-step explanation:

δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.

Calculating the density of air at 5km above earth surface

P = 5000m + 6370000m = 6.375*10^6m

δ = 619.09 -(.000097* 6.375*10^6)

δ = 0.715kg/m^3 = density

Since Mass = density*volume...equ2

To calculate volume of air around the spherical earth at height 5km

V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6

Substituting R and r in equation 2 to solve for volume of air

V = 1.085*10^21 - 1.08*10^21

V = 5.25*10^18m^3

Substituting δ and V into equation 2 to solve for mass of air

M = 0.715 * (5.25*10^18)

M = 3.751*10^18kg

8 0
3 years ago
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