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2 years ago

PLEASE SOLVE QUESTION 13 AND 14 DONT STEAL THE POINTS

Mathematics

1 answer:

Varvara68 [4.7K]2 years ago

3 0

Answer:

See below for solution.

Step-by-step explanation:

$Q13)$ $\frac{\sqrt{11} - \sqrt{5} }{\sqrt{11}+\sqrt{5} }$ = $x - y\sqrt{55}$

LHS :-

= $\frac{\sqrt{11} - \sqrt{5} (\sqrt{11}-\sqrt{5}) }{\sqrt{11}+\sqrt{5} (\sqrt{11}-\sqrt{5}) }$

= $\frac{11-2\sqrt{55}+5 }{11 - 5}$

= $\frac{16-2\sqrt{55} }{6}$

= $\frac{2(8-\sqrt{55}) }{2(3)}$

= $\frac{8-\sqrt{55} }{3}$

=> x = 8/3 and y = 1/3

=> Option B

$Q14)$ $\frac{4}{216^{-2/3} }$ + $\frac{1}{256^{-3/4} }$ + $\frac{2}{243^{-1/5} }$

= 4 x (∛216)² + ( $\sqrt[4]256}$ )³ + 2 x ( $\sqrt[5]{243}$ )

= 4 x 36 + 64 + 2 x 3

= 144 + 64 +6

= 144 + 70

= 214

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Step-by-step explanation:

The complete question is

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For g=4 ----> $a=4(4)+10=\$26$

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$\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]$

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2 years ago

PLEASE SOLVE QUESTION 13 AND 14 DONT STEAL THE POINTS ​

PLEASE SOLVE QUESTION 13 AND 14 DONT STEAL THE POINTS