All categories

2 years ago

Estimate the products of 79 × 37 and 62 × 49 . Which choice shows the sum of the estimates?

Mathematics

1 answer:

klio [65]2 years ago

4 0

Answer:

Sue of estimates = 6200

Step-by-step explanation:

$79\times37$ can be estimated as $80\times 40$ which is $=3200$

Similarly $62\times49$ can be estimated as $60\times 50$ which is $=3000$

∴ Sum of estimates = $3200+3000=6200$

You might be interested in

H=-16t^2+v0t+h0 feet

Liula [17]

<span> <span>THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet</span></span>

8 0

3 years ago

Schach [20]

Answer:

step 1:

2,-5

step 2:

7,1

step 3:

6/5

Step-by-step explanation:

5 0

2 years ago

Find the measures of the numbered angles.

Arte-miy333 [17]

1 = 90
2 = 65
3 = 65
4 = 25

90+25=115
180-115=65

have a merry christmas :)

3 0

2 years ago

Given that the base of the rock is 14 feet, and the height of the rock is 12 feet, what is the slope on which the vehicle is lea

ExtremeBDS [4]

Hi! So pretty much to find slope of a triangle you are going to use rise/run. The height being 12 and the length is 14. You get 12/14. Simplified is going to be 6/7. :)

4 0

2 years ago

Read 2 more answers

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago