Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
30/4800 = 3/480
= 1/160 in fraction form
= 0.00625 in decimal form
Answer:
See below in bold.
Step-by-step explanation:
(1) cosec ( x + 10) = 3
Now cosec x = 1/sin x so
1 / sin (x + 10) = 3
3 sin (x + 10) = 1
sin (x + 10) = 1/3
x + 10 = 19.47 , 160.53 degrees
x = 9.47, 150.53 degrees.
(ii) cot (x - 30) =0.45
cot (x - 30)= 1 /tan (x- 30) so we have
tan (x - 30) = 1 / 0.45 = 2.2222
x - 30 = 65.77 degrees
x = 95.77 degrees.
We are given a concave spherical mirror with the following dimensions:
Radius = 60 cm; D o = 30 cm
Height = 6 cm; h o = 6 cm
First, we need to know the focal length, f, of the object (this should be given). Then we can use the following formulas for calculation:
Assume f = 10 cm
1/ f = 1 /d o + 1 / d i
1 / 10 = 1 / 30 + 1 / d i
d i = 15 cm
Then, calculate for h i:
h i / h o = - d i / d o
h i / 6 = - 15 / 30
h i = - 3 cm
Therefore, the distance of the object from the mirror is 3 centimeters. The negative sign means it is "inverted".
<span>The area to be determined is a segment of the circle.
Since central angle is 120 degrees and 120/360 = 1/3
area of sector of circle is (1/3)*36pi = 12pi
For the area of triangle, you can split it into 2 30-60-90 right triangles with sides 3:3sqrt3:6
thus base of triangle is 6sqrt3 and height is 3
Area = 1/2 * 3* 6sqrt3 = 9sqrt3 -->
segment area = 12pi - 9sqrt3</span>
