A student wants to create a 2:1 scale drawing of the classroom. Is this an appropriate scale to use? Why or why not?
1 answer:
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Answer:
A. The difference in height between the pelican and the heron is -33 feet.
E. The difference in height between the pelican and the trout is 40 feet.
F. The distance between the heights of the pelican and the trout is 40 feet.
Step-by-step explanation:
<h3> The missing statements are:</h3><h3> A. The difference in height between the pelican and the heron is -33 feet</h3><h3> B. The difference in height between the pelican and the heron is 33 feet</h3><h3> C. The distance between the heights of the pelican and heron is -33 feet</h3><h3> D. The difference in height between the pelican and the trout is -40 feet</h3><h3> E. The difference in height between the pelican and the trout is 40 feet</h3><h3> F. The distance between the heights of the pelican and the trout is 40 feet.</h3><h3 />
Let be 0 the sea level.
Since the heron is perched in a tree 50 feet above sea level and directly below the heron the pelican is flying 17 feet above sea level, you can find the difference in height between the pelican and the heron by subtracting 50 feet from 17 feet.
Then, you get that this is:
Now, according the the information given in the exercise, you know that the trough is swimming directly below them and its height is 23 feet below sea level. If you represent this with an integer, this is:
Therefore you can find the difference in height between the pelican and the trout through the following subtraction:
And the distance between them is 40 feet too.
Answer:
Horizontal component = 9.6
Step-by-step explanation:
Recall that the horizontal component is given by the cosine projection;
which in our case (using the fact that in each degree of angle one has 60 minutes of angle, and therefore 30 minutes of angles is the same as 0.5 degrees) becomes:
And rounding to the nearest tenth as requested, we have: