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allochka39001 [22]
2 years ago
13

Write a point slope equation ​

Mathematics
1 answer:
Over [174]2 years ago
4 0

point slope equation formula: y - y1 = m (x - x1)

(-1,4) (-2,1)

answer:

1 -4 = 3 (-2+1)

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Write an equation in slope-intercept form of the line that has a slope of -9 and a y-intercept of -4
tigry1 [53]

y=-9x-4

Slope intercept form uses the formula, y=mx+b, where m is the slope and b is the y- intercept.

I hope this helps. Have a great day!

7 0
3 years ago
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Please help it’s pretty easy and ikr reward brainiest
Ilia_Sergeevich [38]

Answer:

Choice 1 is correct: 8/3 x 1/4 = 2/3

Step-by-step explanation:

4 0
3 years ago
9+4 third power x (20 -8) divided by 2+6
konstantin123 [22]
Answer: 253.5

9+4=13
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13 to the third power = 169
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3 years ago
Explain how you could write a quadratic function in factored form that would have a vertex with an x-coordinate of 3 and two dis
KATRIN_1 [288]
The vertex is on the axis of symmetry, so the axis of symmetry is x = 3. Find any two x-intercepts that have the equivalent distance from the axis of symmetry. Use those x-intercepts to write factors of the function by subtracting their values from x. For example, 2 and 4 are each 1 unit from x = 3, so f(x) = (x – 2)(x – 4) is a possible function.
5 0
3 years ago
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Jane is training for a triathlon. After swimming a few laps, she leaves the health club and bikes 16 miles south. She then runs
lianna [129]

Answer:

The equation for the distance Jane's trainer bikes is x=\sqrt{16^2+12^2}.

Step-by-step explanation:

We have attached diagram for your reference.

Given:

Distance traveled on bike towards south = 16 miles

Distance she ran towards west = 12 miles

We need to find distance Jane's trainer bikes.

Solution:

Let the distance Jane's trainer bike be 'x'.

Now we will assume it to be right angled triangle.

So by Pythagoras theorem which states that;

"Square of the third side is equal to the sum of square of the other two sides."

framing in equation form we get;

x^2=16^2+12^2\\\\x=\sqrt{16^2+12^2}

Hence the equation for the distance Jane's trainer bikes is x=\sqrt{16^2+12^2}.

On solving we get;

x=\sqrt{16^2+12^2}\\\\x= \sqrt{256+144}\\ \\x=\sqrt{400} \\\\x=20\ miles

Hence Jane's trainer bikes a distance of 20 miles.

7 0
3 years ago
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