Answer:
Step-by-step explanation:
volume = area of base * height = area of base * 9 = 72
-> area of base = 72/9 = 8
let a,b,c be the length of sides of isosceles right triangle base
we have a = b and a*b/2 = 8 ft2
-> a*a/2 = 8ft2
-> a*a = 16
-> a=4ft=b
have c^2 = a^2 + b^2 = 16 +16 = 32
-> c = 
= 5.656 ft
Since i dont know that is DF, i calculate both a,b and c
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
I would say the answer is c
Answer:
610,000
Step-by-step explanation:
14,000 would be the nearest ten thousandth but its is not over 15,000 so it would round down to 10,000 making the answer 610,000.
