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emmainna [20.7K]
3 years ago
15

Evaluate the expression for the given value of the variable. |4b-8|+|-1-b^2|+2b^3;b=2

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

In this question we already know the value of 'b' so put the value b=2 in the equation

=|4(2)-8| + |-1-(2)^2| + 2(2)^3

=|8-8| + |-1-4| + 2(8)

=0 -5 +16

=11

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When Kaitlin served as an intern to the United Nations delegation from the United States, she was demonstrating which of the fol
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Answer:

active participation in an international organization

Step-by-step explanation:

I did it on prepworks

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3 years ago
Pedro simplified 4/7 5/8 his work is shown below identify where he made his error
motikmotik
4/7 cannot be simplified anymore. 5/8 can't be simplified either.
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3 years ago
What is the intermediate step in the form (x+a)^2=b(x+a)
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Answer:

The intermediate step are;

1) Separate the constants from the terms in x² and x

2) Divide the equation by the coefficient of x²

3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression

Step-by-step explanation:

The function given in the question is 6·x² + 48·x + 207 = 15

The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;

6·x² + 48·x + 207 = 15

We get

1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192

6·x² + 48·x = -192

2) Dividing by 6 x² + 8·x = -32

3) Add the constant that completes the square to both sides

x² + 8·x + 16 = -32 +16 = -16

x² + 8·x + 16 = -16

4) Factorize (x + 4)² = -16

5) Compare (x + 4)² = -16 which is in the form (x + a)² = b

7 0
3 years ago
The College Boards, which are administered each year to many thousands of high school students, are scored so as to yield a mean
Marysya12 [62]

Answer:

a) 15.87% of the scores are expected to be greater than 600.

b) 2.28% of the scores are expected to be greater than 700.

c) 30.85% of the scores are expected to be less than 450.

d) 53.28% of the scores are expected to be between 450 and 600.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 500, \sigma = 100

a. Greater than 600

This is 1 subtracted by the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% of the scores are expected to be greater than 600.

b. Greater than 700

This is 1 subtracted by the pvalue of Z when X = 700. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{700 - 500}{100}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of the scores are expected to be greater than 700.

c. Less than 450

Pvalue of Z when X = 450. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85% of the scores are expected to be less than 450.

d. Between 450 and 600

pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So

X = 600

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 450

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

0.8413 - 0.3085 = 0.5328

53.28% of the scores are expected to be between 450 and 600.

6 0
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Find two decimals with a product between 1 and 2
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Here is a method that makes it seem easier. 
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<span>Divide both numbers by 10 and write the answer as </span>
<span>0.3 * 1.9 = 0.57</span>
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