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Aneli [31]
2 years ago
15

Can you put 2x-y=7 into y equals

Mathematics
2 answers:
Keith_Richards [23]2 years ago
3 0
Subtract 7 from both sides 2x-y-7=0

Then add y to both sides 2x-7=y
Andrej [43]2 years ago
3 0

Answer:

y = 2x - 7

Step-by-step explanation:

Step 1: Subtract 2x from both sides.

  • 2x - y - 2x = 7 - 2x
  • -y = -2x + 7

Step 2: Divide both sides by -1.

  • -y/-1 = (-2x + 7)/-1
  • y = 2x - 7
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The triangles are similar. The area of the larger triangle 603cm2. what is the area of the smaller triangle?
tekilochka [14]

The smaller triangle is scaled by a factor of (18 cm)/(54 cm) = 1/3 of the larger triangle. The ratio of areas is the square of that scale factor.


small triangle area = (1/3)^2 × large triangle area

... = (1/9) × 603 cm^2

... = 67 cm^2


The appropriate choice is

... C. 67 cm^2

6 0
3 years ago
How many units long is a segment whose endpoints are (-4,1) and (1,13)?
Ann [662]

Answer:

13

Step-by-step explanation:

(1−−4)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(1++0)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(5)2+(12)2‾‾‾‾‾‾‾‾‾‾‾√25+144‾‾‾‾‾‾‾‾‾√169‾‾‾‾√≈13

Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0
3 years ago
Read 2 more answers
1x+1y=5 graph and y-intercept form
Stels [109]
If x+y=5, let y = 0 to find the x-intercept:  x=5.  The x-int. is at (5,0).
               Let x = 0 to find the y-int:  y=5.  The y-int is (0,5).

Plot (5,0) and (0,5), and then draw a straight line thru both points.

If x+y=5,  solving for y results in    y = -1x + 5
Comparing this to y = mx + b,      m=-1 and b= 5.  Again, the y-int. is (0,5).
7 0
3 years ago
A man who is 74 inches tall stand beside a palm tree. The length of the mans shadow is 32 inches . The palm trees shadow is 80 i
saveliy_v [14]

Answer:

227.69 inches tal

Step-by-step explanation:

5 0
3 years ago
please explain/give the new equation from the original equation: f(x) = x2 a shifted 3 units down b shifted 4 units right
masha68 [24]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

and with that template in mind.

3 units down, D = -3

4 units to the right, C = -4

f(x) = (x - 4)² - 3
7 0
4 years ago
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