All categories

2 years ago

CD is perpendicular to AB CREATE AC AND BC AND MEASURE THEIR LENGTHS

Mathematics

1 answer:

Valentin [98]2 years ago

7 0

Answer:

The line segments are equal in length

AC = BC = 5

Step-by-step explanation:

You might be interested in

A box contains 5 blue balls, 2 white balls and 3 black balls. A ball is chosen randomly. Find the probability that the chosen ba

Nimfa-mama [501]

Answer:

7/10 or 70%

Step-by-step explanation:

Add the number of each color of balls together to get the total

5 + 2 + 3 = 10

Add the number of all the balls that aren't black

5 + 2 = 7

Then divide how many balls that aren't black by the total. This gives us the probability the ball you choose is not black

7/10 = 0.7 or 70%

5 0

3 years ago

A school district had four elementary schools to start the year. North Elementary School had 1,200 students, East Elementary Sch

kobusy [5.1K]

Answer:

Step-by-step explanation:

Add all the schools together, then divide by 5

5805/5

6 0

3 years ago

Read 2 more answers

The area of a rectangle is 48 cm² and the length of the rectangle is 8 cm longer than the width. What is the equation you would

ehidna [41]

48= l*w
l= 8+w

To solve for width, substitute the value of l in the first equation so that everything is in terms of w.

Final answer: 48= (8+w)*w

5 0

2 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

You bought a shirt with the price of $135.50, and the sale tax rate is 8.25% whats the sales tax

svp [43]

Answer:

11.18

Step-by-step explanation:

135.50 x .0825=11.18

6 0

2 years ago