Answer:
Step-by-step explanation:
Given
--- proportion that have very little confidence
--- sample
Required
Determine the probability that exactly 5 have very little confidence
This question will be solved using binomial probability:
In this case: x = 5.
So, we have:
56* angles scale regardless of size 90* @ 9mmx9mm is still 90* in 9kmx9km
I think it's $11.79 but I'm not entirely sure
Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Answer:
Just Assume that the transverse axis is horizontal
