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8090 [49]
3 years ago
7

PLS HELP I REALLY NEED THE ANSWER

Mathematics
1 answer:
tatiyna3 years ago
8 0

Answer:

2b: -29 - 13x - 6n

3a: -6

3b: m = 1

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Solve the following linear equation and please explain how you did it 6y+8=6(y+4)−16
Tasya [4]

Answer:

infinite solutions, true for all y

Step-by-step explanation:

6y+8=6(y+4)−16

Distribute

6y+8 = 6y+ 24 - 16

Combine like terms

6y+8 = 6y+8

Subtract 6y from each side

8=8

Since this is always true, the equation is true for all real y

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3 years ago
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Answer:

the solution is t ≤1 (1)

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3 years ago
it's a week before the maths festival a maths exhibition costa £75.40 and so far 12 have been bought. what's the total income so
motikmotik
£75.40*12= £904.80


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3 years ago
Mark bought gifts for his friends, and each gift cost $9. Let y represent the total cost and x represent the number of gifts. Wr
olga nikolaevna [1]

Answer:

y = 9x

Step-by-step explanation:

You can set up linear equations like this: y = mx + b, where m is the slope or rate, and b is the y-intercept.

9 would be the slope, since he has to pay $9 per gift.

The y-intercept is when x = 0, but if he doesn't buy any gifts, he won't have to pay anything, so b = 0. You don't have to include it since it's 0.

So, it's just y = 9x

Hope that helps! :D

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The graph of y=x^2 was transformed to Y= -(x+3)^2 +5. Describe all transformations applied to the original function and determin
mina [271]

Hey there!

1. The graph was flipped vertically and now opens downward.

We know this because there is a negative sign in front of the equation:

y= \boxed- (x+3)^2+5

2. The graph was moved 3 units to the left.

We know this because there is 3 added to x inside of the parenthesis. Remember, inside (parenthesis) is opposite and acts on x, outside (parenthesis) is same and acts on y.

y=-(x\boxed{+3})^2+5

3. The graph was moved 5 units up.

We know this because there is 5 added at the end of the equation. It acts on y because it is outside of the parenthesis.

y=-(x+3)^2\boxed{+5}

Hope this helps!

3 0
3 years ago
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