Answer:
m∠RQS = 72°
m∠TQS = 83°
Step-by-step explanation:
m∠RQS +m ∠TQS = m∠RQT
The two angles combine to make a larger angle
So
m∠RQS = (4x - 20)
m∠TQS = (3x + 14)
(4x - 20) + (3x + 14) = 155
Group the Xs and the constants
4x + 3x - 20 + 14 = 155
Combine like terms
7x - 6 = 155
Add 6 to both sides
7x = 161
Divide by 7 on both sides
x = 23
Check:
4(23) - 20 + 3(23) + 14 = 155
92 - 20 + 69 + 14 = 155
155 = 155
But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.
m∠RQS = 4(23) - 20 = 72°
m∠TQS = 3(23) + 14 = 83°
Checking:
72 + 83 = 155
Answer:
f(-3)=4
Step-by-step explanation:
Substitute x=-3 into the function
f(-3)=(-3)^2-5
f(-3)=9-5
f(-3)=4
<u> case a)</u> The area of the square hole is 8 square centimeters
we know that
the area of a square is equal to
where
b is the length side of the square
in this problem we have
<u>Find the length side b</u>
<u>the answer Part a) is</u>
the length side of the square is 
Part b) The volume of a cube shaped block is 64 cubic centimeters
we know that
the volume of a cube is equal to
where
b is the length side of the cube
in this problem we have
<u>Find the length side b</u>
![b^{3} = 64 \\b= \sqrt[3]{64} \\b= 4\ cm](https://tex.z-dn.net/?f=b%5E%7B3%7D%20%3D%2064%20%5C%5Cb%3D%20%5Csqrt%5B3%5D%7B64%7D%20%5C%5Cb%3D%204%5C%20cm)
therefore
<u>the answer Part b) is</u>
the length side of the cube is 
<span>Hello there.
What is the equation for x+1, x+2, x+3
</span><span>4x</span>+<span>3</span>
Answer:
B
Step-by-step explanation:
