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Sergeu [11.5K]
2 years ago
8

The area of a rectangle is 2x (length + breadth) true or false

Mathematics
2 answers:
erma4kov [3.2K]2 years ago
3 0

Answer:

false

Step-by-step explanation:

to get the area of a rectangle u need to multiple length and width.

Hoochie [10]2 years ago
3 0

Answer:

false

Step-by-step explanation:

the given expression describes the perimeter.

the area is

length × width (or breadth or depth or whatever word applies best for the second dimension in a certain scenario)

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In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and
exis [7]

Answer:

Step-by-step explanation:

cartesian plane :

quadrant 1 : both x and y are positive

quadrant 2 : x is negative, y is positive

quadrant 3 : both x and y are negative

quadrant 4 : x is positive and y is negative

(-2,4)......we have x is negative and y is positive...so we are in quadrant 2

(3,-1)....we have x is positive and y is negative...in quadrant 4

(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x

(1,2)....both are positive....located in quadrant 1

(-3,-5)...both are negative.....quadrant 3

5 0
3 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
The perimeter of a rectangular red sticker is 26 millimeters. It is 4 millimeters tall. How wide is it?
sattari [20]
It is 9 millimeters wide
3 0
3 years ago
Read 2 more answers
Identify the maximum and minimum values of the function y = 10 cos x in the interval [-2π, 2π]
grigory [225]
Hello,

-1<=cos x <=1
==>-10<=10*cos x <=10
max y=10 if x=0 +2kπ ==>x=0,-2π,2π
min y=-10 if x=π+2kπ ==>x=-π,π
6 0
4 years ago
A:1/360<br> B:1/90<br> C:1/180<br> D:1/100
valkas [14]

the answer is 1/360.

\frac{1}{1}  = 360degrees  \\ x= 1degree

cross multiplication and u get the answer

5 0
3 years ago
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