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dezoksy [38]
4 years ago
11

paul is born on his grandfather 60th birthday. In how many years will is Grandfather be 11 times as old as Paul?

Mathematics
2 answers:
Allushta [10]4 years ago
8 0
Maybe is 71 because 60 + 11 is 71 and is basically saying when paul turns 11 how old will his grandfather be ...
arsen [322]4 years ago
3 0
Well considering that Paul was just born while his grandfather is 60. His grandfather will never be 11 years old again. So the answer is never.
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laiz [17]

Answer:

(2,10) or x=2 y=10

Step-by-step explanation:

<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>

5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)

5x=2y-10 (Divide the 5 from the x)

x=2/5y-2

<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>

3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)

6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)

36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)

y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)

y=10

<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>

5x-2(10)=-10 (Multiple 2 by 10)

5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)

5x=10 ( Divide 10 by 5)

x= 2

<em>4. If needed, plug in the values of x and y to check your solution.</em>

Hope this could help! :)

3 0
3 years ago
A planet has a circular orbit around a star. It is a distance of 65,000,000 km from the centre of the star. It orbits at an aver
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Answer:

Step-by-step explanation:

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r = 65000000 km

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Orbit = 406 200 000             km

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t = time = d / s

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crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

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Answer:

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