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2 years ago

If DF=7x-3 and EG=5x+9, find the value of X

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

3 0

Answer:

$x=6$

Step-by-step explanation:

Using the given measurements of the angles and the lengths of the sides, we can determine that this figure must be a rectangle.

Diagonals of a rectangle are always equivalent/congruent.

We can use this information to set up an equation:

$DF=EG\\7x-3=5x+9$

Add 3 to both sides:

$7x-3+3=5x+9+3\\7x=5x+12$

Subtract 5x from both sides:

$7x-5x=5x-5x+12\\2x=12$

Divide both sides by 2

$\frac{2x}{2}=\frac{12}{2}\\x=6$

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-3(3+x)+4(x-6)=-4 Please help me with this question

dsp73

Answer:

$\boxed{ \bold{ \huge{ \sf{x = 29}}}}$

Step-by-step explanation:

$\sf{ - 3(3 + x) + 4(x - 6) = - 4 }$

Distribute -3 through the parentheses

Similarly, Distribute 4 through the parentheses

⇒ $\sf{ - 9 - 3x + 4x - 24 = - 4}$

Collect like terms

⇒ $\sf{x - 9 - 24 = - 4}$

Calculate

⇒ $\sf{x - 33 = - 4}$

Move 33 to right hand side and change it's sign

⇒ $\sf{x = - 4 + 33}$

Calculate

⇒ $\sf{x = 29}$

Hope I helped!

Best regards!!

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