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3 years ago

Given that € 1 = £0.72 a) How much is € 410 in £? b) What is the £ to € exchange rate?

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

8 0

Answer:

a) 295.2

Step-by-step explanation:

a) cross multiplication method

€1=£0.72

€410=x

x=€410×£0.72

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Thomas had 120 chicks 2/5 part given to Luke 1/4 part given to John. how many chicks does Mr. Thomas have now?

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Answer:

3248506784372764779684968'&'

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3 years ago

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in the following diagrams ABD=y,DBC=x,EFH=y, EFG=x and PQS=SQR=x.write the following in terms of x and y ABC

Leokris [45]

Angles are the space between intersecting lines, and they are measured in degrees or radians

The measure of angle ABC is y + x

<h3>How to determine angle ABC</h3>

The given parameters are:

ABD=y,

DBC=x,

EFH=y,

EFG=x

PQS = SQR = x

To determine the measure of angle ABC, we make use of angle ABD and angle DBC

Note that angle ABD and angle DBC have common vertices at points B and D

So, we have:

ABC = ABD + DBC

Substitute known values

ABC = y + x

Hence, the measure of angle ABC is y + x

Read more about angle measures at:

brainly.com/question/17972372

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3 years ago

Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Jus

vichka [17]

Answer:

(25.732,30.868)

Step-by-step explanation:

Given that in a random sample of 42 people, the mean body mass index (BMI) was 28.3 and the standard deviation was 6.09.

Since only sample std deviation is known we can use only t distribution

Std error = $\frac{s}{\sqrt{n} } =\frac{6.09}{\sqrt{42} } \\=0.9397$

$df = 42-1 =41$

t critical for 99% two tailed $= 2.733$

Margin of error $= 2.733*0.9397=2.568$

Confidence interval lower bound = $28.3-2.568=25.732$

Upper bound = $28.3+2.568=30.868$

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3 years ago

Factor completely. -5 x2y + 10 xy - 15 xy2 I need help.

ASHA 777 [7]

Answer:

$5\,x\,y\,(-x+2-3y)$

Step-by-step explanation:

Always proceed by first extracting all common factors to all terms:

Notice that the factors: 5, x, and y are present in all terms, so we can extract them from the trinomial:

$-5x^2y+10xy-15xy^2\\5\,x\,y\,(-x+2-3y)$

Now, the trinomial left (-x+2-3y) cannot be factored out, so then factoring is complete.

4 0

4 years ago

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were

Triss [41]

Question

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were: A. Desserts B. Appetizers C. entrees

Answer:

A)Desserts = 25 %

B)Appetizers = 32.5 %

C)Entrées = 32.5 %

Step-by-step explanation:

Given:

Number of appetisers = 13

Number of entrees = 17

Number of desserts = 10

A. percentage of the dishes he delivered were Desserts

Percentage of Desserts = $\frac{\text{ Number of dessert}}{\text{ total number of dishes}} \times 100$

Total number of dishes = 13 + 17 + 10 = 40

Percentage of Desserts = $\frac{10}{40} \times 100$

Percentage of Desserts = $0.25 \times 100$

Percentage of Desserts = 25 %

B. percentage of the dishes he delivered were Appetizers 

Percentage of Desserts = $\frac{\text{ Number of Appetizers }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{13}{40} \times 100$

Percentage of Desserts = $0.325 \times 100$

Percentage of Desserts = 32.5 %

C. percentage of the dishes he delivered were Entrées 

Percentage of Desserts = $\frac{\text{ Number of Entrees }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{17}{40} \times 100$

Percentage of Desserts = $0.425 \times 100$

Percentage of Desserts = 42.5 %

7 0

3 years ago