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dangina [55]
3 years ago
12

Geometry math question no Guessing and Please show work

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0
The 5 plus 5 is 3 is 16.
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Please help!
tensa zangetsu [6.8K]
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
5 0
2 years ago
Write the equation for the vertical line that contains point E(-7,7)
Levart [38]
Vertical line are represented by x = a number....that number being the x value in ur set of points

so ur equation is : x = -7
5 0
3 years ago
Which expression is equivalent to √48x5, if x> 0?
Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}

          =\sqrt{16\times 3} \times \sqrt{x^{4}\times x}

          =\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}

          =4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2}  } \times \sqrt{x}

          =4\times \sqrt{3} \times x^{2}\times \sqrt{x}

          =4\times x^{2} \times  \sqrt{3} \times \sqrt{x}

          =4\times x^{2}\times \sqrt{3x}

8 0
1 year ago
Help me please!<br> If you get it right, I’ll will brainliest u!!
juin [17]

Answer:

c) if x=2, then 4x=8

Step-by-step explanation:

4 0
2 years ago
Mrs. Stoddard has 264 crayons for her art class of 22 students. How many crayons will each student get if the crayons are divide
DedPeter [7]

Answer:

12

Step-by-step explanation:

264/22

8 0
3 years ago
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