Answer:
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.
The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.
As H0 is supposed to be less than we choose H1 to be greater than equality.
I used my calculator and got x=1 y=3
solve for y to put them in your calculator
2.1x+4.2y=14.7
y = (14.7 -2.1x)/4.2
−5.7x−1.9y=−11.4
y=(-11.4 +5.7x)/(-1.9)
then using the ploting tool I plotted them and found where they intersected
That's geometric sequence
T7 = T5*r^2 = T5+1920
r = 2, so
4*T5 = T5 + 1920
3T5 = 1920
T5 = 640
640 = 2^4 * 40
So, a=40 and the sequence is
40 80 160 320 640 1280 2560 5120 10240 20480 40960 ...
Note that 2560 = 640 + 1920
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15% because 420/2800=.15 and that number converted into a percentage is 15%
Answer:
1. c=-2
2. 0=12 no solution
3. x=4
4. r=3/2
Step-by-step explanation:
