1280 Is the correct anwser
I’m not 100% percent sure on this but I think you would divide!
The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
Answer:
<h2>A, B, D, E</h2>
Step-by-step explanation:
2(2x + 1) = (2)(2x) + (2)(1) = 4x + 2 → A
<em>used distributive property</em>
2(2x + 1) = 2(1 + 2x) → B
<em>used commutative property</em>
2(2x + 1) = (2x + 1) + (2x + 1) = 2x + 1 + 2x + 1 → D
<em>used 2a = a + a</em>
2(2x + 1) = 4x + 2 = x + x + x + x + 1 + 1 → E
<em>used 4x = x + x + x + x and 2 = 1 + 1</em>
