Need help I have a picture up

The question is in the screenshot.

Musya8 [376]

Answer:

v = 4

Step-by-step explanation:

a (-2) multiplied by t (3) = -6

-6 + u (10) = 4

5 0

3 years ago

Read 2 more answers

Given the function f(x)=x2+2x, the value of f(4) is

Citrus2011 [14]

Answer:

24

Step-by-step explanation:

f(x)=x^2+2x

Let x= 4

f(4)=4^2+2*4

= 16 + 8

= 24

5 0

3 years ago

I dunno this answer... pwease help... if you're smart

zmey [24]

Answer:

H: (2, 14)

O: (4,15)

U: (6,14)

S: (2,10)

E: (6,10)

Step-by-step explanation:

the image on the grid is after doin x- 1 and y-7

to get the preimage do the inverse , x + 1 , y + 7

note- a coordinate is written as (x,y)

so, add 1 to all the x's and 7 to all the y's on the coordinates on the grid!

and sorry for asking but, if this is right could i please get a thanks & brainliest recently a moderator deleted ALL my answers (over 400 answers) causing me to lose over 3k points so id appreciate it alot thanks xoxo

3 0

3 years ago

Moselle is riding a roller coaster that is 155 feet high.

DerKrebs [107]

Answer:

91

Step-by-step explanation:

155-16s²

155- 16x2²

155- 16x4

155-64

91

5 0

2 years ago

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

3 years ago