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3 years ago

Help!!!!!

Mathematics

1 answer:

weeeeeb [17]3 years ago

6 0

Answer:

B. Hexagonal is the Correct Answer! <3

Step-by-step explanation:

A triangle is a shape formed when three straight lines meet. All triangles have three sides and three corners (angles).

A hexagon is a polygon with 6 straight sides. It's commonly found in nature, because it's a particularly efficient shape.

Hope this helps!

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Please help I will give brainlyest

Lera25 [3.4K]

Answer:

See below.

Step-by-step explanation:

The answer is D. M and O are congruent, but that is not an option, so the focus goes towards M and N. M and N are similar, but are not congruent.

-hope it helps

6 0

3 years ago

Read 2 more answers

Is that the only ones I used

jek_recluse [69]

Answer:

yes

Step-by-step explanation:

7 0

3 years ago

Given g ( x ) = 2 x + 3 , solve for x when g(x)=3.

padilas [110]

Answer:

x = 0

Step by step explanation:

g ( x ) = 2x + 3

If x = 0,

g ( 0 ) = 2 (0) + 3

or, g ( 0 ) = 3

<em>Hope that helped :)</em>

8 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n

Ratling [72]

Answer:

$k = \dfrac{1}{21}$

b) 0.476

c) 0.667

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

$P(y) = ky$

a) Property of discrete probability distribution:

$\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}$

b) at most four forms are required

$P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476$

c) probability that between two and five forms (inclusive) are required

$P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667$

8 0

3 years ago

Kira decorates the exterior faces of a gift box in the shape of a cube .What is the surface area in square inches of the gift bo

Gekata [30.6K]

Answer:

The surface area of the gift box that Kira decorates is $253.5\ in^{2}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A cube has six square faces

The surface area of a cube is equal to the area of the six squares faces

$SA=6b^{2}$

where

b is the length side of a cube

In this problem we have

$b=6.5\ in$

substitute

$SA=6(6.5)^{2}$

$SA=253.5\ in^{2}$

7 0

3 years ago