Answer:
I don't think you gave the whole question lol but it would take 6hrs to pay off the uniform
Step-by-step explanation:
40/7 = 5.71429
But you round it to 6hrs
Hope this helps dude
Answer:
6√2
Step-by-step explanation:
So the diagonal of a square is equal to √2 times the length of the side of the square. Working backwards that would mean: 12/√2 = side of square
this means that the side of the square is 6√2
The side of the square is also the diameter of the circle.
I'm not sure this was the type of formula you're looking for but I hope it helped!
With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes
Rewrite the limand as
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = (1 - sin(<em>x</em>)) / (cos²(<em>x</em>) / sin²(<em>x</em>))
… = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / cos²(<em>x</em>)
Recall the Pythagorean identity,
sin²(<em>x</em>) + cos²(<em>x</em>) = 1
Then
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / (1 - sin²(<em>x</em>))
Factorize the denominator; it's a difference of squares, so
1 - sin²(<em>x</em>) = (1 - sin(<em>x</em>)) (1 + sin(<em>x</em>))
Cancel the common factor of 1 - sin(<em>x</em>) in the numerator and denominator:
(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = sin²(<em>x</em>) / (1 + sin(<em>x</em>))
Now the limand is continuous at <em>x</em> = <em>π</em>/2, so

Answer:
Number 2
Step-by-step explanation: