Solve the equation for x.<br><br> 32(x − 8) = 14x + 3

Anarel [89]

Answer:

J---

Step-by-step explanation:

If she made 1 Dozen (12) and he kids ate 3, (12-3= 9), she needs to make how many more cupcakes, and since we can use a variable, c + 9 = 24 (Because she promised to bring 24------She would need to make 15 more cupcakes)

7 0

2 years ago

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What of these types of income is taxed?

geniusboy [140]

In most cases, income tax brackets are progressive, meaning that the greater the income, the higher the rate of taxation. Federal rates for the 2013 tax year range from 10 to 39.6 percent. State and city rates are generally much lower.

7 0

3 years ago

The length of a rectangle is twice its width.

goldfiish [28.3K]

P = 2l + 2w
l = 2w

48 = 2(2w) + 2w
48 = 4w + 2w
48 = 6w
8 = w

l = 2w
l = 2(8)
l = 16

48 = 2(16) + 2(8)
48 = 32 + 16
48 = 48

Answer:
length = 16
width = 8

8 0

3 years ago

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The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

2 years ago

Which of the following are the factors of 4b^2-16?

vladimir2022 [97]

The answer is B hope this helps

6 0

3 years ago

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Solve the equation for x. 32(x − 8) = 14x + 3