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Artyom0805 [142]
2 years ago
5

PLEASE HELPPP kahsjahsjad I need help

Mathematics
1 answer:
Klio2033 [76]2 years ago
7 0

Answer:

166\frac{2}{3} *x=y

Step-by-step explanation:

\frac{500}{3} =166\frac{2}{3}

Therefore, 166\frac{2}{3} *x=y

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A parallelogram is made up of a rectangle with a base of 12 centimeters (cm) and a height of 5 cm, and two triangles, each with
valkas [14]
No, he forgot to add the area of the triangles to the area of the rectangle.

It is said that Jeremy thought he solved for the area of the whole parallelogram correctly by multiplying the base and height of the rectangle, which is just a part of the whole parallelogram.

Jeremy’s answer is incomplete, he only calculated the area of the triangle as the answer.

This is because one way of finding an area of a parallelogram is dividing the shape into a rectangle with a triangle on each side.

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With that being said, the formula of a parallelogram that is said is:
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3 0
3 years ago
Can someone help me find x.
Harman [31]

Answer:

Step-by-step explanation:

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6x=63-9

6x=54

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I encourage you to figure out the justification yourself.

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3 years ago
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Dmitry [639]

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Step-by-step explanation:

4 0
3 years ago
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Help ASAP I’ll mark you as brainlister
Rainbow [258]

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If your install Bratleby on your device, It will help you with this. But you will have to put in an email. and it will give 10  questions to answer for free. Sorry that I cannot help you with this.

Step-by-step explanation:

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3 years ago
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satela [25.4K]

\huge\text{Hey there!}

\large\text{Here is your GUIDE for you to go by}\downarrow

\bullet\bold{\  \geq \ or \leq  \ will\ have\ a\ \underline{CLOSED}\ or\ \underline{SHADED\ circle}}\\\bullet\bold{\ >\ or\ \ or

\bold{\ Random\ GUIDE\ \#2}\downarrow

\bold{1. \geq is\ GREATER\ or\ EQUAL\ TO}\\\bold{2. \leq\ is\ LESS\ or\ EQUAL\ TO}\\\bold{3. >\ is\ GREATER\ THAN}\\\bold{4. < \ is\ LESS\ THAN}

“\bold{6>x}”

\bold{Well, based\ on\ your\ GUIDE\ we\ can do\ PROCESS\ OF\ ELIMINATION.}\\\\\bold{REMEMBER: < or > will\ have\ a\ O P E N E D\ circle.\ This\ throws\ A\ \& C}\\\bold{as\ your\ results\ because\ they\ are\ CLOSED\ CIRCLES\ and\ we\ are}\\\bold{looking\ for\ O P E N E D\ circles. This\ leads\ B\ & D\ as\ your\ POSSIBLE}\\\bold{result}

\bold{>\  equals \ GREATER\ THAN}

\bold{Graph\ B.\ is\ SHADED\ to\ the\ LEFT\ which\ we\ need}

\bold{Graph\ D.\ would\ be\ TOO\ BIG}

\boxed{\boxed{\bold{Answer: Option\ B.\ }}}\huge\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite40:)}

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