Answer:
They are all diffrent its like every second they get better!
They are so amazing!
Step-by-step explanation:
Answer:87/8
Step-by-step explanation:cause i smart :D
<!>BRAINLIEST APPERICATED<!>

Substitute this into the parabolic equation,

We're told the line
intersects
twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

We can tell from the quadratic equation that
has its vertex at the point (3, 6). Also, note that

and

so the furthest to the right that
extends is the point (5, 2). The line
passes through this point for
. For any value of
, the line
passes through
either only once, or not at all.
So
; in set notation,

<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
</span>
Radius is the distance between the center and any point on the circle.
r=distance =√((x2-x1)² +(y2-y1)²) =√((5-(-3))²+(-7-(-1))²)=√(64+36)=√100 = 10
r=√100
Equation of the circle , where (h, k) coordinates of the center of the radius.
(h,k)=(5,-7)
(x-h)² +(y-k)² = r²
(x-5)² +(y+7)² = (√100)²
(x-5)² +(y+7)² = 100