Anyone know the answers

If f(x)=1/7-9, then f^-1(x)=

artcher [175]

Answer:

Step-by-step explanation:

Hello!

$f(x)=\frac{1}{7} -9=\frac{1-9*7}{7} =-\frac{62}{7} \\=>f^{-1} (x)=-\frac{7}{62}\\$

Good luck!

4 0

3 years ago

Who can answer this? I’ll mark brainliest!!

Vesna [10]

Answer:

y = 0.48(x - 0.5)² - 3

y = 0.48(x² - x - 6)

Step-by-step explanation:

From the graph the zeros are

x = {-2, 3}

The x coordinate of the vertex is the midpoint of the roots

x = (-2 + 3) / 2

x = 0.5

The y coordinate of the vertex is

y = -3

vertex = (0.5, -3)

--------------------------------------

Merhod I - vertex

Vertex form is

y = a(x - h)² + k

plug in the vertex

y = a(x - 0.5)² - 3

to find a plug in either root

using x = 3

0 = a(3 - 0.5)² - 3

0 = a(2.5)² - 3

0 = 6.25a - 3

3 = 6.25a

a = 3/6.25

a = 0.48

y = 0.48(x - 0.5)² - 3

-----------------------------

Method II - roots

y = a(x + 2)(x - 3)

-3 = a(0.5 + 2)(0.5 - 3)

-3 = a(2.5)(-2.5)

-3 = -6.25a

3/6.25 = a

0.48 = a

y = 0.48(x + 2)(x - 3)

Expand

y = 0.48(x² - x - 6)

5 0

3 years ago

What is the area of Triangle PQR on the grid?

kupik [55]

Answer:

4 units

Step-by-step explanation:

You have a triangle. This means that the formula is 1/2 x b x h. So its 2 x 4 = 8. Then its 8 x 1/2 which gives you 4.

6 0

3 years ago

Read 2 more answers

PLZ HELP ME ILL MARK BRAINKEIST

GuDViN [60]

Answer:

I, personally, would assume A, or 80°

Step-by-step explanation:

4 0

2 years ago

Solve the system by finding the reduced row-echelon form of the augmented matrix.

Alex

Answer:

The reduced row-echelon form is

$\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The solutions to the system of equations are:

$y=-2z-3,\:x=-6z-10$

Step-by-step explanation:

To solve this system of linear equations,

$x-4y-2z=2\\2x-11y-10z=13\\-x+6y+6z=-8$

you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is the augmented matrix that represents the system.

$\left[ \begin{array}{cccc} 1 & -4 & -2 & 2 \\\\ 2 & -11 & -10 & 13 \\\\ -1 & 6 & 6 & -8 \end{array} \right]$

It can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

Interchange two rows (or columns).
Multiply each element in a row (or column) by a non-zero number.
Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: add -2 times the 1st row to the 2nd row

Row Operation 2: add 1 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1/3

Row Operation 4: add -2 times the 2nd row to the 3rd row

Row Operation 5: add 4 times the 2nd row to the 1st row

$\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$x+6z=-10\\y+2z=-3\\0=0$

The system has infinitely many solutions.

$y=-2z-3,\:x=-6z-10$

4 0

4 years ago