light-colored, silica-rich igneous rock that is less dense than basaltic rock. dense, dark-colored igneous rock formed from magma;rich in magnesium and iron and poor in silica. Describes magma or igneous rock that is rich in feldspars and silica and that is generally light in color.
Explanation:
1.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils whereas erosion is the movement of weathered materials from one area to the other.
Erosion moves weathered materials and it causes them to change position. For example loose chips of rocks broken down as the rock weakens through alternate wetting and drying in tropical regions will remain in-situ until the agents of erosion comes to carry them away. The breaking is weathering and the carrying is erosion.
Learn more:
Wind erosion brainly.com/question/2115729
2.
Examples of mechanical weathering:
- Frost action
- Pressure release
Examples of chemical weathering:
There are two types of weathering:
- In mechanical weathering, a rock disintegrates into smaller chunks by the action of wind, water and glacier. For example in temperate and polar regions, water within rocks freezes. When water freezes it expands and causes tension within the rock. When temperature drops, water melts and the tension is relieved. This process causes a rock to crack. The crack will eventually become wider with time.
- In chemical weathering, a rock decomposes by the action of chemicals formed in the rock. In karst regions where limestone forms, combination of rain water and carbon dioxide forms weak carbonic acid that reacts with calcite in limestone.
Learn more:
Erosion brainly.com/question/2473244
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Answer:
6 protons, 6 neutrons, and 6 electrons.
Explanation:
Pasteurization, vaccines against antrax and rabies, discovered the germ fermentation
Answer:
The answer to the question is
The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits
Explanation:
To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure
At the first trial the mixture contains
3.6 atm CO
1.2 atm H₂O (g)
Total pressure = 3.6+1.2= 4.8 atm
which gives
3.36 atm CO
0.96 atm H₂O (g)
0.24 atm H₂ (g)
That is
CO+H₂O→CO(g)+H₂ (g)
therefore the mixture contained
0.24 atm CO₂ and the total pressure =
3.36+0.96+0.24+0.24 = 4.8 atm
when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂
At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857
adding 1.8 atm CO gives 4.46 atm hence we have
(0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857
which gives x = 0.031 atm or x = -0.6183 atm
Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm
