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il63 [147K]
2 years ago
10

) The color of the __________ litmus paper into ___________ tell us that the solution of the compound is ________________ in nat

ure.
Chemistry
1 answer:
maks197457 [2]2 years ago
6 0

Answer:

The color of the blue litmus paper turning into red tells us that the solution of the compound is acidic in nature.

The color of the red litmus paper turning into blue tells us that the solution of the compound is basic in nature.

Explanation:

Litmus paper is paper treated with a mixture of natural dyes obtained from lichens. This makes the paper purple in neutral conditions (pH = 7), red in acidic conditions (pH < 7), and blue in basic (alkaline) conditions (pH > 7). It is used to determine whether a solution is acidic or basic, but can't measure the pH.

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polet [3.4K]

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

4 0
3 years ago
Which best describes the asteroid belt
harina [27]

i think that the answer is d. millions of small rocky objects

5 0
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Mg2OH has how many unique elements?<br> A. <br> 4<br> B. <br> 2<br> C. <br> 3<br> D. <br> 5
frutty [35]

Answer:

Magnesium hydroxide has 3 unique elements.

Explanation:

Long story short, 2 is the balancing compound in structure to make up hydroxide, therefore 1 compound would be left to create Mg(2O)H.

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5 0
3 years ago
Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
sergiy2304 [10]
The balanced chemical reaction is:

<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.

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4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

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Question 8 of 8&gt; 0 Attempt 2 A chemist needs to determine the concentration of a sulfuric acid solution by titration with a s
Nesterboy [21]

Answer:

12.29 M

Explanation:

  • The reaction that takes place is:

H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O

  • Now let's calculate the <u>moles of H₂SO₄ that were titrated</u>:

0.1284 M * 0.1915L*\frac{1molAcid}{2molNaOH} = 0.01229 mol H₂SO₄.

  • Thus, the <u>concentration of the diluted solution is</u>:

0.01229 mol H₂SO₄ / 0.010 L = 1.229 M

  • Finally, the <u>concentration of the original acid solution is:</u>

1.229 M*\frac{250mL}{25mL} = 12.29 M

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3 years ago
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