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2 years ago

Is the graph increasing, decreasing, or constant where 8 10 8 8- 4+ 2+ -2 -6 -8 -10

1 answer:

8 0

Decreasing fore sure because the last four where decreasing so the going trend is going down ( decreasing )
Hope it helps

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Mrs. Duggin walked every day for seven days. If she walked 9/10 of a mile each day for seven days, how many total miles did she

Molodets [167]

Answer:

Mrs. Duggin walked a total of $\frac{63}{10} \ miles.$ .

Step-by-step explanation:

Given:

Number of miles walked on each day = $\frac{9}{10} \ mile$

Number of days she walked = 7

We need to find the Total miles she walked using repeated addition method.

Solution:

Now we know that Repeated Addition means adding each group together and it is also known as Multiplication.

So we can Find Total miles she walked by adding Number of miles walked on each day with number of day times.

we can Find Total miles she walked by Multiplying Number of miles walked on each day with number of days.

framing in equation form we get;

Total miles she walked = $\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}+\frac{9}{10}= \frac{9+9+9+9+9+9+9}{10} = \frac{63}{10}\ miles$

Total miles she walked = $\frac{9}{10}\times7= \frac{63}{10} \ miles.$

Hence Mrs. Duggin walked a total of $\frac{63}{10} \ miles.$ .

4 0

4 years ago

Patty can make 10 purses in 8 hours. At this rate, how many purses can she make in 28 hours?

djverab [1.8K]

Answer:

35 purses

Step-by-step explanation:

Set up a proportion, where x is the number of purses she can make in 28 hours:

$\frac{10}{8}$ = $\frac{x}{28}$

Cross multiply and solve for x:

8x = 280

x = 35

So, in 28 hours, she can make 35 purses

8 0

4 years ago

Read 2 more answers

Help with this math thing please!

musickatia [10]

Answer:

i cant see

Step-by-step explanation:

6 0

3 years ago

Use the diagram to complete the proof by filling in the blanks. Picture is attached

galben [10]

Answer:

Step-by-step explanation:

From the question attached,

Given:

RT and PQ intersect at a point S.

RS = PS and ST = SQ

To prove :

RT = PQ

Statements Reasons

1). RS = PS and ST = SQ 1). Given

2). RS + ST = PS + SQ 2). Addition property

3). RS + ST = RT ; PS + SQ = PQ 3). Pair of line segments

4). RT = PQ 4). Substitution property

7 0

4 years ago

Solve the initial value problem (explicit solution). y y' - cot t = 0 y(pi/2) = -1

Sergeu [11.5K]

This ODE is separable:

$yy'-\cot t=0\implies y\,\mathrm dy=\cot t\,\mathrm dt$

Integrate both sides to get

$\dfrac12y^2=\ln|\sin t|+C$

Given that $y\left(\frac\pi2\right)=-1$ , we get

$\dfrac12(-1)^2=\ln|\sin\dfrac\pi2\right|+C\implies C=\dfrac12$

Then

$\dfrac12y^2=\ln|\sin t|+\dfrac12$

$y^2=2\ln|\sin t|+1$

$y^2=\ln\sin^2t+1$

$\implies\boxed{y(t)=\pm\sqrt{\ln\sin^2t+1}$

6 0

3 years ago