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disa [49]
2 years ago
11

Escribe la configuracion electronica de 2 elementos metalicos

Chemistry
2 answers:
Ostrovityanka [42]2 years ago
8 0

Answer:

(See explanation)

Explanation:

Copper: [Ar] 3d¹⁰ 4s¹

Silver: [Kr] 4d¹⁰ 5s¹

hichkok12 [17]2 years ago
4 0

Answer:

translation: Write the electronic configuration of 2 metallic elements.

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Gas occupies 100.0 mL at a pressure of 780 mm Hg. What is the volume of the gas
jolli1 [7]

Answer:

Final volume after applying 880 mmHg pressure = 89.28

Explanation:

Initial volume (V 1)= 100 ml

Initial pressure (P1) =780 mm Hg = 780/780 = 1atm

Final pressure (P2)=880 mm Hg = 880/780 =1.12 atm

Final volume (V2)=?

We know that,

Applying Boyle's law,

P1 V1=P2 V2

1*100=1.12*V2

100=1.12*V2

100/1.12=V2

89.28=V2

V2=89.28 ml

Hope this helps you. Please mark me as a brainlist.

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2 years ago
Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu
12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

concentration_{working\ solution}=?

Volume_{working\ solution}=25.00mL

Volume_{stock\ solution}=4.60mL

concentration_{stock\ solution}=50.04 ppm

So,  

concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL

concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm

4 0
2 years ago
The ph of a fruit juice is 3.43.4. find the hydronium ion​ concentration, left bracket upper h 3 upper o superscript plus right
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PH is simply a convenient way to denote hydronium ion concentration (usually in moles per liter or molarity). pH is calculated from the given concentration using the equation:   pH  =  -log [H3O⁺]

To find [H3O+] from the given equation, we apply the antilog. 
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A solution with a pH of 3.43 has a hydrogen ion concentration of 3.7154x10^-4 moles per liter.
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Hey man its difference in temperature
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The answer is to test a piece of untreated and treated under same conditions!
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