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2 years ago

Escribe la configuracion electronica de 2 elementos metalicos

Chemistry

2 answers:

Ostrovityanka [42]2 years ago

8 0

Answer:

(See explanation)

Explanation:

Copper: [Ar] 3d¹⁰ 4s¹

Silver: [Kr] 4d¹⁰ 5s¹

hichkok12 [17]2 years ago

4 0

Answer:

translation: Write the electronic configuration of 2 metallic elements.

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How do lipids differ from carbohydrates? they are formed from different basic elements

grin007 [14]

Lipids are insoluble in water and they produce twice as more energy as carbohydrates.

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3 years ago

8 bananas weigh 1pound and sale price is 4 pounds for $5. How much it cost me to buy 25 bananas?

asambeis [7]

It should be 3-4 dallors because 8x3 is 24 and that is 3 pounds and you only have one banana left so is supposed to be 3 dallors and change.

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3 years ago

How many moles of KCIO3 are required to produce 58.3 grams of 02? 2 KCIO3 —> 2 KCI + 3 O2

strojnjashka [21]

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Mole Ratio

Stoichiometry

Analyzing reactions rxn
Using Dimensional Analysis

Explanation:

Step 1: Define

Identify variables

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

Step 2: Identify Conversions

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 58.3 \ g \ O_2(\frac{1 \ mol \ O_2}{32.00 \ g \ O_2})(\frac{2 \ mol \ KClO_3}{3 \ mol \ O_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 1.21458 \ mol \ KClO_3$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃

6 0

3 years ago

Helppppppp I have a brain fart ....

kherson [118]

Answer:

Hello there!

The first answer is hot

The second answer is sunshine!

Explanation:

Those make the most sense

Have a great day!

6 0

3 years ago

Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam

nikklg [1K]

The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
pH = 5.83

4 0

3 years ago